count-number-of-digits

#include<stdio.h>
void main()
{
	int n,sum = 0,m,prod = 1,count = 0,temp;
	printf("Enter the positive number : ");
	scanf("%d",&n);
	temp = n;
	if(n==0){
		printf("The entered digits are zero");
	}	
	while(n>0){
		m = n%10;
		sum += m;
		prod *= m;
		n = n/10;
		count++;
	}
	printf("The number of digits is %d \n",count);
	if((sum+prod)==temp){
		printf("The given number %d satisfies the condition \n",temp);
	}
	else
		printf("0 \n");
}