37.2 gmail validator.java

/*
Ask the user to give his/her the Gmail id , check Gmail id is in proper format or not ? and count the number of charecters excluding @gmail.com
let rules for valid mail id are
1. only special symbol allowed is (.) and that must not be in staring or ending.
2. @gmail.com must be prsent at last.

Input Format

First line must be a mail id

for Example

Input Format
bhimasen.moharana@gmail.com

Output Format
valid 17

Constraints

input must be a Gmail id

Output Format

First line prints "valid" or "invalid"
Secondline prints Number of chars presenst inthe mail id excluding @gmail.com

Sample Input 0

bhimasen.moharana@lpu.co.in
Sample Output 0

invalid
17
Explanation 0

invalid because it is not a Gmail id.
and number of charecter =17
*/

import java.io.*;
import java.util.*;

public class Solution {

    public static void main(String[] args) {
        /* Enter your code here. Read input from STDIN. Print output to STDOUT. Your class should be named Solution. */
        Scanner sc = new Scanner(System.in);
        String gmail = sc.next();
        char []check = gmail.toCharArray(); 
        boolean ans = true;
        int count =0;
        if(gmail.endsWith("@gmail.com"))
        {
            int n = gmail.indexOf("@gmail.com");
            for(int i=0;i<n;i++)
            {
                if(!((check[i] >= 'A' && check[i] <= 'Z') || (check[i] >='a') && (check[i] <= 'j')))
                {
                    System.out.println("invalid");
                    ans = false;
                }    
            }
            if(ans)
                System.out.println("valid");
        }
        else
        {
            System.out.println("invalid");
        }
        int ct = gmail.indexOf("@");
        System.out.print(ct);
    }
}