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Description
Bug Report
from typing_extensions import Protocol
class Func(Protocol):
def __call__(self, __a: int, **kwargs: str) -> None:
# ^^^ positional-only arg
...
# Same error when using PEP 570 positional-only syntax:
# def __call__(self, a: int, /, **kwargs: str) -> None:
def myfunc(a: int, **kwargs: str) -> None:
pass
f: Func = myfunc
Expected Behavior
In my view this should be allowed. Anyone calling f()
promises to pass the 1st argument as positional. And myfunc accepts the 1st argument as positional or kwarg, so it should be considered compatible.
Actual Behavior
Mypy output:
positional_only.py:12: error: Incompatible types in assignment (expression has type "Callable[[int, KwArg(str)], Any]", variable has type "Func")
positional_only.py:12: note: "Func.__call__" has type "Callable[[int, KwArg(str)], Any]"
Your Environment
- Mypy version used: 0.942
- Mypy command-line flags: (none)
- Mypy configuration options from
mypy.ini
(and other config files): (none) - Python version used: 3.10.2
- Operating system and version: macOS
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erictraut commentedon Apr 5, 2022
I agree this is a false positive. This should be allowed because there is no type safety violation.