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Copy path200.number-of-islands.cpp
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200.number-of-islands.cpp
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/*
* @lc app=leetcode id=200 lang=cpp
*
* [200] Number of Islands
*
* https://leetcode.com/problems/number-of-islands/description/
*
* algorithms
* Medium (40.67%)
* Total Accepted: 318.8K
* Total Submissions: 783.8K
* Testcase Example: '[["1","1","1","1","0"],["1","1","0","1","0"],["1","1","0","0","0"],["0","0","0","0","0"]]'
*
* Given a 2d grid map of '1's (land) and '0's (water), count the number of
* islands. An island is surrounded by water and is formed by connecting
* adjacent lands horizontally or vertically. You may assume all four edges of
* the grid are all surrounded by water.
*
* Example 1:
*
*
* Input:
* 11110
* 11010
* 11000
* 00000
*
* Output: 1
*
*
* Example 2:
*
*
* Input:
* 11000
* 11000
* 00100
* 00011
*
* Output: 3
*
*/
#include<bits/stdc++.h>
using namespace std;
class Solution {
public:
int m,n;
int numIslands(vector<vector<char>>& grid) {
if(grid.size()==0)
return 0;
m=grid.size();
n=grid[0].size();
vector<vector<int>> isl(m,vector<int>(n,0));
int numIslands = 0;
for(int i=0;i<m;i++){
for(int j=0;j<n;j++){
if(grid[i][j] == '1'){
numIslands++;
call_dfs(grid,i,j);
}
}
}
return numIslands;
}
void call_dfs(vector<vector<char>> &grid,int i,int j){
queue<pair<int,int>> q;
pair<int,int> root(i,j);
q.emplace(root);
while(!q.empty()){
auto p = q.front();
grid[p.first][p.second]='2';
//take left
if(p.first-1>=0 && grid[p.first-1][p.second] == '1'){
q.emplace(pair<int,int>(p.first-1,p.second));
grid[p.first-1][p.second]='2';
}
//take up
if(p.second-1>=0 && grid[p.first][p.second-1] == '1'){
q.emplace(pair<int,int>(p.first,p.second-1));
grid[p.first][p.second-1]='2';
}
//take right
if(p.first+1<m && grid[p.first+1][p.second] == '1'){
q.emplace(pair<int,int>(p.first+1,p.second));
grid[p.first+1][p.second]='2';
}
//take down
if(p.second+1<n && grid[p.first][p.second+1] == '1'){
q.emplace(pair<int,int>(p.first,p.second+1));
grid[p.first][p.second+1]='2';
}
q.pop();
}
}
};
int main(){
Solution sol;
vector<vector<char>> grid{{'1','1','0','0','0'},
{'1','1','0','0','0'},{'0','0','1','0','0'},{'0','0','0','1','1'}};
cout << sol.numIslands(grid) << endl;
}